Some problems in Physics don't involve plug-and-chug. They involve the use of an equation as a guide to thinking about how a change in one variable (or two variables) would affect other quantities. That's the case in this question. Two variables are being changed - the separation distance (R) from a location to the source of charge (i.e., the Van de Graaff generator) and the quantity of charge (Q) on the source. You need to consider both variables and their affect upon the electric field value (E). There's at least two methods of approach. Both rely upon an understanding of the equation (i.e., relationship).
The Equation
The relationship between the Electric Field value (E), the separation distance (R) and the quantity of charge (Q) is given by the equation ...
E = k•Q/R2
where k is a proportionality constant. From the equation, you would reason that E is directly proportional to the Q. A larger Q results in a larger E value. And twice the Q would result in twice the E value.
The separation distance (R) works differently. The electric field value (E) is inversely proportional to the square of the separation distance (R). So a larger R value results in a smaller E value. And 2 times the R would result in one-fourth the E value. (The one-fourth is the result of inversing and squaring the 2.) The squaring of the R in the equation means that a change in R will cause a bigger change in E compared to a change in Q.
The Application - Method 1
One way to approach this task of ranking the three locations involves calculating three different Q/R2 ratios. So for each of the three locations, take the charge amount (2Q or 3Q) and divide by the square of the distances (R or 2R). Use a sheet of scratch paper and write down the three ratios. (Paper remembers ratios better than a brain does.) In the case of 2R, be sure to square the 2. When you are done, inspect the coefficients in front of the result. The ratio with the larger coefficient is the one that gets the Greatest E ranking and the ratio with the smallest coefficient gets the Smallest E ranking.
The Application - Method 2
Another way to approach this task of ranking the three locations involves doing a comparison of the individual loactions to one another in light of the E-Q-R relationship. So when you look at the three locations provided, you will note there are two locations with the same distance (2R) but a different amount of charge (0.5•Q vs. 2•Q). In comparing these two locations, the one with the greatest quantity of charge (2•Q) would have the greatest E value. So you can rank these locations relative to one another. But to complete the rankings, you must figure out where the third location (3•Q, 3•R) falls relative to these two. This third location has1.5 times the charge and 1.5 times the radius of the 2•Q, 2•R location. Since the 1.5 factor is the same for both charge and distance, you will have to consider that the distance is more impactful in terms of affecting the E value. And so this third location has a smaller E value than the 2•Q, 2•R location. But how does it compare to the 0.5•Q, R location? The 3•Q location is 6 times the charge and 2 times the distance. Even though the distance gets squared, that's not enough to overwhelm the 6 times the charge (3•Q compared to 0.5•Q). And so the Middlest E ranking goes to the 3•Q, 2•R location.