The slope of a  position-time graph at any given instant in time or during any given time interval is equal to the velocity of the object at that time or during that time interval. Being a vector, velocity has a direction. For graphs, that direction is often associated with the positive and negative sign on the slope.

The slope of the line on a position-time graph is the velocity. So this question involves calculating slope. The question asks you to determine the slope during a specified range of times - for example, during the last 6.0 seconds. There are two lines on the graph, one for each stage of the object's motion. The purpose of the time is to indicate which section of the graph to use in calculating the slope. 

To determine slope, you will need to determine the "x, y" coordinates of two points on the line. Pick points for which you are certain of what the coordinates are. The first point at the beginning of the second stage of motion and the last point on the graph would be great choices. Once you've selected the two points and determined their coordinates, calculate the ratio of the y-coordinate difference divided by the x-coordinate difference. That is, determine the ratio of ∆position to ∆time. 

Avoid falling prey to the common error of failing to compute a ratio of two changes. Too many students are prone to simply finding the coordinates of a single point and calculating the ratio of the y-coordinate to the x-coordinate. This will only work if the line on the graph passes through the point (0 s, 0 m). The line on this graph does not do that. The process of determining this slope always involves finding the change in the vertical coordinate divided by the change in the horizontal coordinate for any two points located on the line. You MUST use two points.
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