6
U
Backspace
Loading ...
A
N
Wait for it ..
Objective: To identify whether positive, negative, or zero work is being done, to identify the force that is doing the work, and to describe the energy transformation associated with such work.
M
T
3
0
Start
G
Space
You are NOT using this Activity as a Logged-in student. You may log in and return to this page. Or you can do this Activity as a Guest. If you continue as a Guest, a record of completing it will NOT be stored in our database.
4
L
S
This is the Teacher Preview mode of this Science Reasoning task.
Teacher Preview allows teachers to preview the Questions for each Activity and their organization into Question Groups. This allows you to evaluate the appropriateness of the Activity for your students. Teacher Preview also allows you to consider whether you would like to customize the task by removing one or more of the Activities from the assignment. Customization can be done within Task Tracker when you assign the task to your class.
-
F
Z
9
You are currently logged in with the username shown below. As long as you maintain an internet connection, any of the parts of this Activity that you complete will be saved in your account.
Tap on the Start Button to begin.
Periodic Trends
Start Teacher Preview Mode
K
P
E
Y
1
2
J
8
Q
X
D
I
Use Key Pad to Enter Name. Then Tap the Enter Button.
Version 1.0
7
R
W
Enter
C
capOff
H
B
Shift
O
V
5
Predict trends associated with charge, nucleus-electron distances, and attractive forces for rows and columns of the Periodic Table.
Student Name:
Redo
Given three elements, identify the element with that is most likely to lose electrons and underlying reason for this tendency.
Use a molecular formula to identify the Lewis electron dot diagram of an unknown element and predict the group number of the element.
Use electronegativity values to predict the type of bond - ionic, polar covalent, and nonpolar covalent - that will form between elements.
Metallic Character Trends
Use atomic radius trends to identify the element with the greatest radius and identify the underlying reason for the greater radius.
Charge, Distance, Forces, and Periodic Trends
Covalent Bonds, Formulae, and Periodic Trends
Electronegativity Trends and Bond Type
Atomic Radius Trends
Progress Report
--
16
7
No, Stay Here
Tap to View Information:
Activity:
Scroll to View Whole Passage. Tap to Close.
Question Group:
15
14
13
8
Charge, Distance, Forces, and Periodic Trends
Predicting the properties of elements requires an understanding of the atom, its sub-structure (protons, electrons, and neutrons), and the interaction between the nucleus and the surrounding electron shells. This interaction is electrical in nature and sometimes worded as oppositely-charged objects attract. The force of attraction between the positively-charged protons of the nucleus and a negatively-charged electron in the outermost shell of an atom depends upon …
1) the distance between the charges, and
2) the amount of positive charge in the nucleus.
Both of these factors are associated with the location of an element on the Periodic Table. And so we notice trends or patterns in how properties change as one moves from element to element down a column or across a row of the Periodic Table.
In this activity, you will identify trends associated with charge, distance, force, and the location of an element on the Periodic Table.
Question
Check Answer
This is the last Activity
in this task.
Yes, Return
12
This is the last QG
of the last Activity.
11
Learn More About Task Tracker and Teacher Preview.
This is the last Question
of the last Activity.
If you return to the Main Menu, then you will lose all your progress
on this activity.
Are you sure you want to return to the Main Menu?
10
9
Which statements below accurately describe the trend observed in a property when moving from element to element across the 3rd period of the Periodic Table? Select all that apply.
Currently Displaying ...
Some Interactivity and Check Answer functionality is disabled when in Teacher Preview mode.
Activity:
Each Science Reasoning task is based on a passage or story that presents data and information or describes an experiment or phenomenon. Students must combine an understanding of science content and science reasoning skills (science practices) to answer questions about the passage or story.
Tap anywhere to view the passage.
Insert
https://www.physicsclassroom.com/
Empty
MS
Physics-Interactives/Static-Electricity/
Full
Reduce
1,1,1,1,2,2,2,2,3,3,3,3,4,4,4,4,7,7,7,7
Name-That-Charge/
Template Version 1.2 Added Question Scene 4 for Table Completion
0
4,4,4,4,4
0,0,0,0,0,0,0,0,0,0,0,0,0
Used/Unused Q
Management
Charge-Distance-Force,Atomic Radius,Metallic Character,Electronegativity Trends,Covalent Bonding
0,0,0,0,0
AddValues
Tap Me!
Tap Me to Toggle Through Reasons
Identify the underlying reason for this claim:
Consider the three elements B, F, and N. Which element would have the greatest atomic radius?
Check Both Answers
Quick Check
Atomic Radius Trends
An atom is not like a baseball or soccer ball that has a well-defined edge. The nucleus of the atom is surrounded by electrons that are perceived to occupy spherical regions known as electron shells. There are several electron shells centered on the nucleus and having varying sizes. Each shell has a capacity to hold a certain number of electrons. For instance, the first electron shell (the smallest shell) can hold only two electrons; the second smallest electron shell can hold up to 8 electrons; the third smallest electron shell can hold up to 18 electrons; and so forth. Each shell becomes larger than the ones before it and can hold more electrons. The electrons are located somewhere inside the shell; they do not orbit the nucleus at a fixed distance from the shell. The radius of an atom is defined as the distance from center of the nucleus to the outermost edge of the shell.
This radius is a periodic property of an element. Like any periodic property, we notice trends or patterns in how radius changes as one moves from element to element down a column or across a row of the Periodic Table.
In this activity, you will use the trend to the identify the element that has the greatest radius from among three given elements. You will also provide an explanation of the underlying reason for why this is the case.
Tap toggle through options.
Covalent Bonds, Formulae, and Periodic Trends
Main group elements undergo bonding in order to acquire a stable electron configuration that resembles that of the nearest noble gas. We often say that an element wants to acquire a stable octet of outer shell (valence shell) electrons. This is known as the octet rule. In the case of hydrogen, it acquires the electron configuration of helium and is said to follow the duet rule.
Lewis electron dot diagrams are often used to represent the number of valence electrons in an atom. Each dot in the diagram represents the number of valence electrons in the atom. Since main group elements in the same group of the periodic table have the same number of valence electrons, they will also have identical Lewis electron dot diagrams.
Nonmetals fall short of an octet of valence electrons by 1, 2, 3, and even 4 electrons. When bonding with other nonmetals, they share their valence electrons with enough atoms in order to acquire an octet of valence shell electrons. The number of bonds that such nonmetals form is generally dependent upon the number of additional valence electrons that are needed to satisfy the octet rule.
In this activity, you will be given the molecular formula of a compound formed between two nonmetals. One of the nonmetals will have an unknown identity – "X". The formula will indicate the number the number of bonds that are formed with X in the molecular compound. You will use this information to predict the Lewis electron dot diagram of element X. You will also predict the Group number of unknown element X.
Element X is likely a ________.
Group 17 element
Group 16 element
Group 14 element
Group 15 element
Tap to select or deselect an answer.
Consider the elements Cs, F, and Li. Which element would most easily lose electrons?
Metallic Character Trends
Metallic character refers to the readiness of an element to undergo a reaction. Metal reactivity is generally greatest for elements that are most willing to give up an electron. Elements with a high metallic character generally have low ionization energies and low electronegativity values. Metallic character is a periodic trend. As such the relative tendency of an element to act as a metal can be predicted by its location in the periodic table.
In this activity, you will be given three elements (and their location in the periodic table). You must identify the element that most easily loses electrons. Finally, you will have to identify the underlying reason for your choice.
This element has the largest nuclear charge; its outer shell electrons are attracted to the nucleus with the strongest force.
This element is the only non-metal . Non-metals tend to lose electrons very easily.
The outermost electrons of this element are located in a large electron shell; they are attracted to the nucleus with the smallest force.
What reasoning would you give for this claim?
The outer shell electrons of this element are located close to the nucleus and experience a strong repulsive force; they are easily lost.
Consider the elements Na, S, and Si. Use their electronegativity values and location on the Periodic Table to determine which element would most likely form …
Tap to toggle through answer options for each question.
Electronegativity Trends and Type of Bonding
The electronegativity of an element refers to the tendency of that element to attract the electrons involved in the bond between atoms. Elements with a high electronegativity have a strong attraction for the electrons in a bond and tend to be more nonmetallic. These elements can be thought of as electron-hungry. On the other hand, metallic elements have a relatively lower electronegativity value and are more willing to give up an electron. Electronegativity is a periodic trend.
Bonds between atoms can be ionic or covalent. Ionic bonds result when a metal with a low electronegativity transfers an electron to a nonmetal with a considerably higher electronegativity. Being willing to give up an electron, the metal becomes a positive ion. The nonmetal acquires the electron and becomes a negative ion. The oppositely charged ions attract, forming an ionic bond.
Two nonmetals will more likely form a covalent bond. The covalent bond results when the two atoms share their electrons with each other in order to obtain a stable octet. The shared electrons in the bond can be distributed equally among the two atoms or unequally between the two atoms. The bigger the difference in electronegativity between the two elements, the greater the difference in the level of attraction each atom has for the shared electrons, and the more unequal the sharing will be. A covalent bond that involves unequal sharing is referred to as polar covalent bond. And a covalent bond between elements with similar electronegativity values will involve equal sharing of electrons and be classified as a nonpolar covalent bond.
Whether a bond between two elements is ionic, polar covalent, or nonpolar covalent depends on the relative attraction the elements have for electrons, and thus upon their relative electronegativity values. It is possible to make rules for relating electronegativity differences between elements to the type of bonds that results between them. But doing so too often misses the big idea that these classifications of ionic, polar covalent, and nonpolar covalent are part of a continuum. Ionic bonds (due to large differences in electronegativity) and nonpolar covalent bonds (resulting when there are small differences in electronegativity values) are on opposite ends of this continuum. Polar covalent bonds occupy the wide expanse across the middle of this continuum.
In this activity, you will use electronegativity values to classify the bond that results between three elements and carbon, fluorine, hydrogen, or nitrogen. Since electronegativity is a periodic trend, you can use the relative location of the three elements in determining the type of bond it forms with carbon, fluorine, hydrogen, or nitrogen.